tag:blogger.com,1999:blog-3153693.post1005364200565032378..comments2023-07-14T08:24:02.676-05:00Comments on Service Oriented Enterprise: Measuring Availability of Cloud SystemsUnknownnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-3153693.post-22177540708791441082011-10-27T06:02:53.828-05:002011-10-27T06:02:53.828-05:00I have a solution based on a probability model wit...I have a solution based on a probability model with hidden state "Theta" that connects the observations X1 and X2: <br /><br />Theta -> X1 ; Theta->X2.<br /><br />Both the observations (X1 and X2) are dependent on Theta. But they are CONDITIONALLY independent of each other, GIVEN Theta.<br /><br />Further Info can be found at: <br />http://www.eecs.qmul.ac.uk/~norman/BBNs/Independence_and_conditional_independence.htmshankarhttps://www.blogger.com/profile/05722331194940292572noreply@blogger.comtag:blogger.com,1999:blog-3153693.post-38937227412026862782011-10-03T08:02:18.232-05:002011-10-03T08:02:18.232-05:00I've since learned that one way of dealing wit...I've since learned that one way of dealing with the 'infectious agent' is through N Version Programming: http://en.wikipedia.org/wiki/N-version_programmingjeffhttps://www.blogger.com/profile/16751830353772022191noreply@blogger.comtag:blogger.com,1999:blog-3153693.post-78181038059293654582011-08-16T08:54:17.602-05:002011-08-16T08:54:17.602-05:00Alexandar,
Your formula doesn't take into acco...Alexandar,<br />Your formula doesn't take into account the idea of an 'infectious agent' that would decrease the likelihood of multiple items not being available. Said another way, your formula seems to say that the likelihood of the cars starting has nothing to do with the weather outside (that the likelihood of any one car starting is a constant).<br /> <br />I disagree with this position. Thoughts?<br />Jeffjeffhttps://www.blogger.com/profile/16751830353772022191noreply@blogger.comtag:blogger.com,1999:blog-3153693.post-75159278552401507852011-08-12T12:17:58.822-05:002011-08-12T12:17:58.822-05:00If N1 (0.<=N1<=1.) is the availability of yo...If N1 (0.<=N1<=1.) is the availability of your first car and N2 (0.<=N2<=1.) is the availability of your second car then the availability of any of them is:<br />1-(1-N1)*(1-N2)<br /><br />Thanks,<br />ASAlexhttps://www.blogger.com/profile/07571303538841911828noreply@blogger.com